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4/n+1+1/n^2-5n-6=1/n-6
We move all terms to the left:
4/n+1+1/n^2-5n-6-(1/n-6)=0
Domain of the equation: n!=0
n∈R
Domain of the equation: n^2!=0
n^2!=0/
n^2!=√0
n!=0
n∈R
Domain of the equation: n-6)!=0We add all the numbers together, and all the variables
n∈R
-5n+4/n+1/n^2-(1/n-6)-5=0
We get rid of parentheses
-5n+4/n+1/n^2-1/n+6-5=0
We calculate fractions
We do not support enpression: n^3
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